If $y = \frac{{a + b{x^{3/2}}}}{{{x^{5/4}}}}$ and $y' = 0$ at $x = 5$, then the ratio $a:b$ is equal to

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

y = \frac{{a + b{x^{3/2}}}}{{{x^{5/4}}}}

and

y' = 0

x = 5

, then the ratio

a:b

is equal to

View answer and explanation

Correct option: A

\sqrt 5 :1

Option A (√5 : 1) is correct because setting the derivative to zero at x=5 and solving for the ratio a:b gives √5 : 1.

Practice All Chapter MCQs →

f(x)=|x|^{|\tan x|}

f^{\prime}\left(\frac{-\pi}{6}\right)

x

y

x>0

x y=1

x+y

f(x)=[x] \sin (\pi x)

[x]

x

x=k, k

f(x)

y = {\sec ^{ - 1}}\left[ {\mathrm{cosec}x} \right] + \mathrm{cose}{\mathrm{c}^{ - 1}}\left[ {\sec x} \right] + {\sin ^{ - 1}}[\cos x] + {\cos ^{ - 1}}[\sin x],

\frac{{dy}}{{dx}}

\frac{d}{d x} \sin ^{-1}\left(3 x-4 x^{3}\right)

z = y + f\left( v \right),

v = \left( {\frac{x}{y}} \right),

v\frac{{\partial z}}{{\partial x}} + \frac{{\partial z}}{{\partial y}}