Skip to main content
Back to WORK-ENERGY-POWER

JEE PHYSICS MCQ: WORK-ENERGY-POWER

1 Medium
1 of 1
Application +4 | -1
A uniform chain of length LL and mass MM is lying on a table and 14th\frac{1}{4}^{\text {th}} of its length is hanging vertically down over the edge of the table. If gg is acceleration due to gravity, the work required to pull the hanging part back on the table
View answer and explanation
Correct option: B
MgL32\frac{{MgL}}{32}
Option B (MgL32\frac{{MgL}}{{32}}) is correct because it represents the work required to lift the hanging part of the chain to the table level, calculated by considering the center of mass of the hanging part.

More Questions from WORK-ENERGY-POWER

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.