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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

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Application +4 | -1

If

{\cos ^{ - 1}}x + {\cos ^{ - 1}}y = \frac{\pi }{2}\;

and

{\tan ^{ - 1}}x - {\tan ^{ - 1}}y = 0,\;

then

{x^2} + xy + {y^2}\;

is equal to

View answer and explanation

Correct option: C

\frac{3}{2}

Option C is correct because given the conditions

{\cos ^{ - 1}}x + {\cos ^{ - 1}}y = \frac{\pi }{2}

and

{\tan ^{ - 1}}x - {\tan ^{ - 1}}y = 0

, it follows that

{x^2} + xy + {y^2} = \frac{3}{2}

.

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