JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Analyzing +4 | -1

\alpha ,\beta

are ther roots of

a{x^2} + bx + c = 0

and

\alpha + \beta ,{\alpha ^2} + {\beta ^2},{\alpha ^3} + {\beta ^3}

are in G.P., where

\Delta = - {b^2} - 4ac

, then

View answer and explanation

Correct option: D

c\Delta = 0

Option D (

c\Delta = 0

) is correct because the given condition that

\alpha + \beta, \alpha^2 + \beta^2, \alpha^3 + \beta^3

are in G.P. leads to the equation

ac(b^2 - 4ac) = 0

, which simplifies to

c\Delta = 0

More Questions from QUADRATIC EQUATIONS

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{x^2} + 4ax + 2 > 0

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9{x^2} - 18\left| x \right| + 5 = 0

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