JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

\alpha ,\beta

are the roots of

a{x^2} + bx + c = 0

the equation whose roots are

2 + \alpha ,2 + \beta

View answer and explanation

Correct option: D

a{x^2} + x\left( {b - 4\;a} \right) + 4\;a - 2\;b + c = 0

Option D (

a{x^2} + x\left( {b - 4\;a} \right) + 4\;a - 2\;b + c = 0

) is correct because by transforming the original equation using the relationship between the roots, we obtain the new equation with roots 2 +

\alpha

and 2 +

\beta

More Questions from QUADRATIC EQUATIONS

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\alpha ,\beta

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\alpha ,\;\beta

{x^2} - px + q = 0

{\alpha _1},{\beta _1}

{x^2} - qx + p = 0,

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{x^2} + 4ax + 2 > 0

x

a

f\left( x \right) = a{x^2} + bx + c\;

\;f\left( { - 1} \right) < 1,f\left( 1 \right) > - 1,f\left( 3 \right) < - 4\;

\;a \ne 0,

9{x^2} - 18\left| x \right| + 5 = 0

f\left( x \right) = \log \left( {{x^2} - x - 2} \right)