Derivative of ${\sec ^{ - 1}}\left( {\frac{1}{{1 - 2{x^2}}}} \right){\rm{w}}{\rm{.r}}{\rm{.t}}{\rm{.}}{\sin ^{ - 1}}\left( {3x - 4{x^3}} \right)$ is

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

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Analyzing +4 | -1

Derivative of

{\sec ^{ - 1}}\left( {\frac{1}{{1 - 2{x^2}}}} \right)\mathrm{w}\mathrm{.r}\mathrm{.t}\mathrm{.}{\sin ^{ - 1}}\left( {3x - 4{x^3}} \right)

View answer and explanation

Correct option: D

\frac{2}{3}

Option D (2/3) is correct because by substituting

x = \sin \theta

, the expression simplifies, and the derivative can be easily found.

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