JEE MATHEMATICS MCQ: DIFFERENTIATION

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Understanding +4 | -1

f\left( x \right) = {\cos ^{ - 1}}\left\{ {\frac{{1 + {{\left( {{{\log }_e}x} \right)}^2}}}{{1 + {{\left( {{{\log }_e}x} \right)}^2}}}} \right\}

, then

f'\left( e \right)

View answer and explanation

Correct option: C

Is equal to

\frac{1}{e}

Option C (Is equal to

\frac{1}{e}

) is correct because after simplification and differentiation, substituting x = e yields the value

\frac{1}{e}

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