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JEE PHYSICS MCQ: WORK-ENERGY-POWER

1 Medium

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Application +4 | -1

At what time

\mathrm{PE}

will be equal to half of the total energy (TE) :-

View answer and explanation

Correct option: D

\frac{T}{8}

Option D (

\frac{T}{8}

) is correct because the potential energy is half the total energy when

\sin^2(\omega t) = \frac{1}{2}

, which occurs at

t = \frac{T}{8}

.

More Questions from WORK-ENERGY-POWER

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. Assertion:When a particle moves in a circle with a uniform speed its acceleration is constant but the velocity changes.
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. As what height will its kinetic energy be

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of its initial value? Assertion: Centripetal force does no work.

Reason: Force and displacement are perpendicular to each other. Statement I: Both stretched and compressed springs possess potential energy.

Statement II: Work done against restoring force is stored as potential energy. A bullet of mass

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hits a ball of mass

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m^{\prime}

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