Skip to main content
Back to QUADRATIC EQUATIONS

JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Medium
1 of 1
Analyzing +4 | -1
Let f(x)=ax2+bx+c,a≠0f(x)=a x^2+b x+c, a \neq 0 Suppose, f(−1)<1f(-1) < 1, f(1)>−1f(1) > -1 and f(3)<−4f(3) < -4. Then,
View answer and explanation
Correct option: B
b+1>0b+1 > 0
Option C (b+1<0b+1 < 0) is incorrect. Option B (b+1>0b+1 > 0) is correct because from the given inequalities, we can derive that b+1>0b+1 > 0.

More Questions from QUADRATIC EQUATIONS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.