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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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Application +4 | -1
The potential energy of a body as a function of distance is given as U(x)=(−6x2+2x)JU(x)=\left(-6 x^2+2 x\right) {J}. The conservative force acting on body at x=1 mx=1 {~m} will be
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Correct option: C
10 N10 {~N}
Option D (2Ω2\Omega) is correct because the resistance is calculated by dividing the voltage for full-scale deflection by the corresponding current.

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