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JEE PHYSICS MCQ: ATOMS

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Analyzing +4 | -1
The equation λ=1.227x nm\lambda=\frac{1.227}{x} \mathrm{~nm} can be used to find the de- Broglie wavelength of an electron.
In this equation xx stands for:
Where m = mass of electron
P = momentum of electron
K = Kinetic energy of electron
V = Accelerating potential in volts for electron
View answer and explanation
Correct option: D
V\sqrt{V}
Option D is correct. The de-Broglie wavelength equation can be expressed as λ = 1.227/√V nm, where V is the accelerating potential in volts.

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