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JEE PHYSICS MCQ: ATOMS

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Application +4 | -1
Taking Rydberg’s constant RH=1.097  ×  107  m{R_H} = 1.097\,\, \times \,\,{10^7}\,\,m, first and second wavelength of Balmer series in hydrogen spectrum is
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Correct option: D
6552  A0,4863  A06552\,\,{A^0},4863\,\,{A^0}
Option D (6552  A0,4863  A06552\,\,{A^0},4863\,\,{A^0}) is correct because it accurately calculates the first two wavelengths of the Balmer series using the Rydberg formula.

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