JEE PHYSICS MCQ: ATOMS

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Application +4 | -1

For a hydrogen atom, when electron jump from

n

=2

to

{n}=1

, then wave length of radiation emitted found to be

\lambda_0

. Then, for which transition of electron of a 'He' atom, the wavelength of radiation emitted will be equal to '

\lambda_0

'.

View answer and explanation

Correct option: B

{n}=4

to

{n}=2

Option B (

{n}=4

to

{n}=2

) is correct because the wavelength of the emitted radiation matches that of hydrogen when the electron transitions from n=4 to n=2 in He+.

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