JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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Application +4 | -1

\cos ^{-1} x-\cos ^{-1} \frac{y}{2}=\alpha

, where

-1 \leq x \leq 1,-2 \leq y \leq 2

x \leq \frac{y}{2}

, then for all

x, y, 4 x^{2}-4 x y \cos \alpha+y^{2}

is equal to:

View answer and explanation

Correct option: A

4 \sin ^{2} \alpha

The correct answer is A (

4 \sin^2 \alpha

) because it involves using the cosine subtraction formula and trigonometric identities to simplify the expression.

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