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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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A force F⃗=i^+5j^+7k^\vec{F}=\hat{i}+5 \hat{j}+7 \hat{k} acts on a particle and displaces it through s⃗=6i^+9k^\vec{s}=6 \hat{i}+9 \hat{k}. Calculate the work done if the force is in newton and displacement in metre.
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Correct option: A
69 J69 \mathrm{~J}
Option A (69 J69 \mathrm{~J}) is correct because it is the dot product of the force and displacement vectors.

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