JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

\sin \theta=n \sin (\theta+2 \alpha)

, then

\tan (\theta+\alpha)

is equal to

View answer and explanation

Correct option: B

\left(\frac{1+n}{1-n}\right) \tan \alpha

Option B (

\left(\frac{1+n}{1-n}\right) \tan \alpha

) is correct because it is the result of applying the componendo and dividendo rule and trigonometric identities to the given equation.

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