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JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1
If sin⁡x+sin⁡2x=1\sin x+\sin ^2 x=1 then cos⁡12x+3cos⁡10x+3cos⁡8x+cos⁡6x\cos ^{12} x+3 \cos ^{10} x+3 \cos ^8 x+\cos ^6 x is equal to -
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Correct option: A
1
Option A (1) is correct because the expression simplifies to 1 after substituting cos⁡2x=sin⁡x\cos^2 x = \sin x.

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