JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

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Application +4 | -1

\tan (\pi \cos \theta)=\cot (\pi \sin \theta)

then

\cos (\theta-\pi / 4)

is equal to

View answer and explanation

Correct option: A

\pm \frac{1}{2 \sqrt{2}}

Option A (

\pm \frac{1}{2 \sqrt{2}}

) is correct because it is derived by using the trigonometric identity

\tan(\theta) = \cot(\frac{\pi}{2} - \theta)

and solving for

\cos(\theta - \frac{\pi}{4})

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\sin \,\,x\,\,\;cos\,\,3x = \sin \,\,3x\,\,\cos \,\,5x

\left[ {0,\;\,\frac{\pi }{2}} \right]

\left( {x,\,y} \right)

x,\,\,y \in \left[ {0,10} \right]

\left( {\sqrt {{{\sin }^2} - \sin \,\,x + \frac{1}{2}} } \right){2^{{{\sec }^2}y}}\,\, \cdot \,\, \le 1

\mathrm{X}

\theta \rightarrow \frac{\pi}{2}

\sin x+\cos x=\frac{\sqrt{7}}{2}

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\tan \frac{\pi}{5}+2 \tan \frac{2 \pi}{5}+4 \cot \frac{4 \pi}{5}

0 < x < \pi

\cos x+\sin x=\frac{1}{2}

\tan x