JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

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Application +4 | -1

{\left( {{{\tan }^{ - 1}}x} \right)^2} + {\left( {{{\cot }^{ - 1}}x} \right)^2} = \frac{{5{\pi ^2}}}{8}

, then

x

is equal to

View answer and explanation

Correct option: D

- 1

Option D (-1) is correct because solving the equation using the property (tan^-1x)² + (cot^-1x)² = 5pi²/8 leads to x = -1.

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