If $y=\log _{\cos x} \sin x$, then $\frac{d y}{d x}$ is equal to

$(\tan x \log \cos x+\cot x \log \sin x) /(\log \cos x)^2$

$(\cot x \log \cos x+\tan x \log \sin x) /(\log \sin x)^2$

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

y=\log _{\cos x} \sin x

, then

\frac{d y}{d x}

is equal to

View answer and explanation

Correct option: A

(\cot x \log \cos x+\tan x \log \sin x) /(\log \cos x)^2

Option A is correct because it is the result of applying the quotient rule and chain rule to differentiate the given logarithmic function.

Practice All Chapter MCQs →

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