JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

\frac{d}{d x}\left(e^{x} \log \sin 2 x\right)

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Correct option: A

e^{x}(\log \sin 2 x+2 \cot 2 x)

The correct answer is A (

e^{x}(\log \sin 2 x+2 \cot 2 x)

) because it is the result of applying the product rule and the chain rule to differentiate the given function.

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\frac{{dy}}{{dx}}

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v\frac{{\partial z}}{{\partial x}} + \frac{{\partial z}}{{\partial y}}