JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

Let

y

be an implicit function of

x

defined by

{x^{2x}} - 2{x^x}\cot y - 1 = 0.

Then

y'\left( 1 \right)

equals

View answer and explanation

Correct option: A

- 1

Option A (-1) is correct because it is the value of y'(1) obtained by implicit differentiation and substituting x=1 and y=pi/2.

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