If ${\rm{10}}\,\,{\rm{A}}$ deposits ${\rm{10}}{\rm{.8 \,\,g}}$ of silver in ${\rm{25}}\,\,{\rm{min}}$, how much copper would deposit when ${\rm{9}}\,\,{\rm{A}}$ current flows for ${\rm{20}}\,\,{\rm{min}}$.?

$\begin{array}{*{20}{l}} {{\rm{3}}{\rm{.81}}\,\,{\rm{g}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{6}}{\rm{.35}}\,\,{\rm{g}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{10}}{\rm{.1}}\,\,{\rm{g}}} \end{array}$

$\begin{array}{*{20}{l}} {{\rm{12}}{\rm{.7}}\,\,{\rm{g}}} \end{array}$

JEE PHYSICS MCQ: ELECTRO MAGNETIC INDUCTION

1 Medium

1 of 1

Application +4 | -1

\mathrm{10}\,\,\mathrm{A}

deposits

\mathrm{10}\mathrm{.8 \,\,g}

of silver in

\mathrm{25}\,\,\mathrm{min}

, how much copper would deposit when

\mathrm{9}\,\,\mathrm{A}

current flows for

\mathrm{20}\,\,\mathrm{min}

View answer and explanation

Correct option: A

\begin{array}{llllllllllllllllllll} {\mathrm{3}\mathrm{.81}\,\,\mathrm{g}} \end{array}

Option A (

\begin{array}{llllllllllllllllllll} {\mathrm{3}\mathrm{.81}\,\,\mathrm{g}} \end{array}

) is correct because it correctly applies Faraday's laws of electrolysis to find the mass of copper deposited.

Practice All Chapter MCQs →

R

n

i=i_0 \sin \omega t

N

4 \mathrm{sec}

0.1\,\,{m^2}

\mathrm{60}

\mathrm{0}\mathrm{.4}\,\,\mathrm{T}

\mathrm{100}

\mathrm{50}\,\,\mathrm{mH}

\mathrm{2 A}