JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Analyzing +4 | -1

Let

f: \mathbb{R}-\{2,6\} \rightarrow \mathbb{R}

be real valued function defined as

f(x)=\frac{x^{2}+2 x+1}{x^{2}-8 x+12}

. Then range of

f

View answer and explanation

Correct option: A

\left(-\infty,-\frac{21}{4}\right] \cup[0, \infty)

The correct answer is A (

\left(-\infty,-\frac{21}{4}\right] \cup[0, \infty)

) because it is the range obtained by analyzing the quadratic equation and its discriminant.

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