JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

The rate of change of

\sqrt {\left( {{x^2} + 16} \right)}

with respect to

\frac{x}{{x - 1}}

x = 3

View answer and explanation

Correct option: C

- \frac{{12}}{5}

Option C (

- \frac{{12}}{5}

) is correct because the rate of change is calculated by finding the derivatives of both functions and then dividing them, evaluated at x=3.

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