If $ y=a^{x} \cdot b^{2 x-1} $, then $ \frac{d^{2} y}{d x^{2}} $ is

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

y=a^{x} \cdot b^{2 x-1}

, then

\frac{d^{2} y}{d x^{2}}

View answer and explanation

Correct option: D

y \cdot\left(\log a b^{2}\right)^{2}

Option D (

y \cdot\left(\log a b^{2}\right)^{2}

) is correct because the second derivative of

y

involves multiplying by

(\log a + 2 \log b)

twice, which is equivalent to

y \cdot (\log ab^2)^2

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