Skip to main content
Back to ATOMS

JEE PHYSICS MCQ: ATOMS

1 Medium
1 of 1
Application +4 | -1
An electron beam of energy 10 KeV10 \mathrm{~KeV} is incident on metallic foil. If the interatomic distance is 0.55 A∘0.55 ~\mathop {\text{A}}\limits^ \circ. Find the angle of diffraction.
View answer and explanation
Correct option: B
sin⁡−1(0.22)\sin ^{-1}(0.22)
Option B (sin⁡−1(0.22)\sin ^{-1}(0.22)) is correct because it correctly uses the de Broglie wavelength and Bragg's law to find the diffraction angle.

More Questions from ATOMS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.