JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Application +4 | -1

\mathrm{x}

is a solution of the equation,

\sqrt{2 x+1}-\sqrt{2 x-1}=1,\left(x \geq \frac{1}{2}\right)

, then

\sqrt{4 x^{2}-1}

is equal to :

View answer and explanation

Correct option: A

\frac{3}{4}

Option A (

\frac{3}{4}

) is correct because solving the given equation for x and substituting it into

\sqrt{4 x^{2}-1}

yields

\frac{3}{4}

More Questions from QUADRATIC EQUATIONS

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{x^2} + 4ax + 2 > 0

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