If $\sin ^{-1}\left(\frac{x^2-y^2}{x^2+y^2}\right)=\log a$ then $\frac{d y}{d x}=$

JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

\sin ^{-1}\left(\frac{x^2-y^2}{x^2+y^2}\right)=\log a

then

\frac{d y}{d x}=

View answer and explanation

Correct option: B

\frac{y}{x}

Option B (

\frac{y}{x}

) is correct because implicit differentiation and simplification lead to this result.

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