JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Analyzing +4 | -1

f\left( x \right) = \left( {ab - {b^2} - 2} \right)x + \int \nolimits_0^x \left( {{{\cos }^4}\theta + {{\sin }^4}\theta } \right)d\theta

is decreasing function of

x

for all

x \in R

and

b \in R,\;b

being independent of

x

, then

View answer and explanation

Correct option: B

a \in \left( { - \sqrt 6 ,\;\sqrt 6 } \right)

Option B (

\frac{1}{4}

) is correct because it represents the point where the function attains its maximum value within the given interval.

More Questions from QUADRATIC EQUATIONS

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\log _7 \log _5(\sqrt{x+5}+\sqrt{x})=0

\alpha ,\beta

{x^2} - 3x + a = 0,a \in R

\alpha < 1 < \beta ,

\alpha ,\;\beta

{x^2} - px + q = 0

{\alpha _1},{\beta _1}

{x^2} - qx + p = 0,

\frac{1}{{{\alpha _1}\beta }} + \frac{1}{{\alpha {\beta _1}}}\mathrm{and}\;\frac{1}{{\alpha {\alpha _1}}} + \frac{1}{{\beta {\beta _1}}},

{x^2} + 4ax + 2 > 0

x

a

f\left( x \right) = a{x^2} + bx + c\;

\;f\left( { - 1} \right) < 1,f\left( 1 \right) > - 1,f\left( 3 \right) < - 4\;

\;a \ne 0,

9{x^2} - 18\left| x \right| + 5 = 0

f\left( x \right) = \log \left( {{x^2} - x - 2} \right)