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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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Analyzing +4 | -1
A body moves along a path PQR\mathrm{PQR} in horizontal plane from P\mathrm{P} to R\mathrm{R}. When the particle is at Q\mathrm{Q}, its speed is decreasing. The acceleration of the particle at Q\mathrm{Q} is best represented by the vector.(A, B, C and D are vectors)
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Correct option: C
C\mathrm{C}
Option C (C) is correct because the acceleration vector at Q must have components both opposite to the velocity (to decrease speed) and towards the center of curvature.

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