If $x + y + z = xyz$, then ${\tan ^{ - 1}}x + {\tan ^{ - 1}}y + {\tan ^{ - 1}}z = $

JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

1 of 1

Application +4 | -1

x + y + z = xyz

, then

{\tan ^{ - 1}}x + {\tan ^{ - 1}}y + {\tan ^{ - 1}}z =

View answer and explanation

Correct option: A

Option D (None of these) is correct because the given solution incorrectly concludes that the expression equals 0. The correct simplification leads to a different result.

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, then

x

is equal to If

{x^2} + {y^2} + {z^2} = {r^2},

then

{\tan ^{ - 1}}\left( {\frac{{xy}}{{zr}}} \right) + {\tan ^{ - 1}}\left( {\frac{{yz}}{{xr}}} \right) + {\tan ^{ - 1}}\left( {\frac{{xz}}{{yr}}} \right)\;

is equal to

2{\tan ^{ - 1}}\left( {\frac{1}{3}} \right) + {\tan ^{ - 1}}\left( {\frac{1}{7}} \right)

is equal to