JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Hard

1 of 1

Analyzing +4 | -1

f: R \in R

is defined by

f(x)=\frac{x^2-a x+1}{x^2+a x+1}, 0 < a < 2

, then which of the following is true:

View answer and explanation

Correct option: A

(2+a)^2 f^{\prime \prime}(1)+(2-a)^2 f^{\prime \prime}(-1)=0

Option A is correct because

(2+a)^2 f^{\prime \prime}(1)+(2-a)^2 f^{\prime \prime}(-1)=0

is derived from calculating the first and second derivatives of the given function and substituting x=1 and x=-1.

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