JEE MATHEMATICS MCQ: DIFFERENTIATION

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Application +4 | -1

Let

y(x)=e^{2 \sin ^{-1} x}, x \in[-1,1]

and

\left(1-x^2\right) y^{\prime \prime}(x)=x y^{\prime}(x)+\lambda y(x)

, then

\lambda

equals

View answer and explanation

Correct option: A

Option A (4) is correct. By differentiating the given function twice and substituting into the given differential equation, the value of \

\lambda

\$ is found to be 4.

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