JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Analyzing +4 | -1

y=\left[x+\sqrt{x^{2}-1}\right]^{15}+\left[x-\sqrt{x^{2}-1}\right]^{15}

, then

\left(\mathrm{x}^{2}-1\right) \frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}+\mathrm{x} \frac{\mathrm{dy}}{\mathrm{dx}}

is equal to

View answer and explanation

Correct option: B

224 y^{2}

Option D (

225 y

) is correct. By differentiating the given equation twice and substituting, we find that

(x^{2}-1) \frac{d^{2} y}{dx^{2}}+x \frac{dy}{dx} = 225y

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