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JEE PHYSICS MCQ: WORK-ENERGY-POWER

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A meter stick of mass 400 g400 \mathrm{~g} lying horizontally is pivoted at one end and displaced through an angle 60∘60^{\circ}. The increase in its potential energy is
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Correct option: A
2 J2 \mathrm{~J}
Option A (2 J2 \mathrm{~J}) is correct because the increase in potential energy is calculated using the formula PE=mghPE = mgh, where hh is the change in height of the center of mass.

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