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JEE MATHEMATICS MCQ: DIFFERENTIATION

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If y=tanβ‘βˆ’1(xβˆ’x1+x3/2),y = {\tan ^{ - 1}}\left( {\frac{{\sqrt x - x}}{{1 + {x^{3/2}}}}} \right), then yβ€²(1)y'\left( 1 \right) is equal to
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Correct option: D
βˆ’14- \frac{1}{4}
Option D (βˆ’14- \frac{1}{4}) is correct because after simplifying the expression using inverse trigonometric properties and then differentiating, y'(1) equals βˆ’14-\frac{1}{4}.

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