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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

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Application +4 | -1

The value of

\sin ^{-1}\left(\cos \left(\cos ^{-1}(\cos x)+\sin ^{-1}(\sin x)\right)\right)

where

x \in\left(\frac{\pi}{2}, \pi\right)

is equal to

View answer and explanation

Correct option: A

-\pi / 2

Option A (

-\pi / 2

) is correct because the expression simplifies to

\sin^{-1}(\cos(\pi)) = \sin^{-1}(-1) = -\pi/2

.

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