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JEE MATHEMATICS MCQ: DIFFERENTIATION

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Analyzing +4 | -1
If f(x)=sin⁡(sin⁡x)f(x)=\sin (\sin x) and f′′(x)+tan⁡xf′(x)+g(x)=0f^{\prime \prime}(x)+\tan x f^{\prime}(x)+g(x)=0, then g(x)g(x) is :
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Correct option: D
cos⁡2xsin⁡(sin⁡x)\cos ^{2} x \sin (\sin x)
Option D is correct. By differentiating f(x) twice and substituting into the given equation, we can solve for g(x) and find that it equals cos⁡2xsin⁡(sin⁡x)\cos ^{2} x \sin (\sin x).

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