JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Analyzing +4 | -1

The number of real solutions of the equation

\frac{{6 - x}}{{{x^2} - 4}} = 2 + \frac{x}{{x + 2}}

, is

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Correct option: A

Option A (1) is correct because the equation has only one real solution, x = 7/3, after excluding x = ±2.

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{x^2} - px + q = 0

{\alpha _1},{\beta _1}

{x^2} - qx + p = 0,

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{x^2} + 4ax + 2 > 0

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a

f\left( x \right) = a{x^2} + bx + c\;

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9{x^2} - 18\left| x \right| + 5 = 0

f\left( x \right) = \log \left( {{x^2} - x - 2} \right)