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JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

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If sin⁡−1x+sin⁡−1y=π2{\sin ^{ - 1}}x + {\sin ^{ - 1}}y = \frac{\pi }{2}, then cos⁡−1x+cos⁡−1y{\cos ^{ - 1}}x + {\cos ^{ - 1}}y is equal to
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Correct option: A
π2\frac{\pi }{2}
Option A (π2\frac{\pi }{2}) is correct because if sin⁡−1x+sin⁡−1y=π2{\sin ^{ - 1}}x + {\sin ^{ - 1}}y = \frac{\pi }{2}, then cos⁡−1x+cos⁡−1y{\cos ^{ - 1}}x + {\cos ^{ - 1}}y can be derived using the identity sin⁡−1x+cos⁡−1x=π2{\sin ^{ - 1}}x + {\cos ^{ - 1}}x = \frac{\pi }{2}.

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