JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

Let

x=2 \sin \theta-\sin 2 \theta

and

y=2 \cos \theta-\cos 2 \theta

, then

\left(\frac{d^2 y}{d x^2}\right)_{\theta=\pi}=

View answer and explanation

Correct option: A

\frac{3}{8}

Option A (

\frac{3}{8}

) is correct because it is the value of the second derivative of y with respect to x at the specified point.

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