The value of $\cos \left(2 \cos ^{-1} x+\sin ^{-1} x\right)$ at $x=\frac{1}{6}$ :

JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

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Application +4 | -1

The value of

\cos \left(2 \cos ^{-1} x+\sin ^{-1} x\right)

x=\frac{1}{6}

View answer and explanation

Correct option: B

-\frac{\sqrt{35}}{6}

Option B (

-\frac{\sqrt{35}}{6}

) is correct because the expression simplifies to

-\sqrt{1-x^2}

and substituting

x=\frac{1}{6}

gives the result.

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