JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

f\left( x \right) = \sqrt {ax} + \frac{{{a^2}}}{{\sqrt {ax} }}

, then

f'\left( a \right)

is equal to

View answer and explanation

Correct option: C

Option C (0) is correct because after differentiating the given function and substituting x = a, the expression simplifies to zero.

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