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JEE MATHEMATICS MCQ: DIFFERENTIATION

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ddx[eaxsin⁡(bx+c)]\frac{d}{d x}\left[\frac{e^{a x}}{\sin (b x+c)}\right] is equal to
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Correct option: C
eax[asin⁡(bx+c)−bcos⁡(bx+c)]sin⁡2(bx+c)\frac{e^{a x}[a \sin (b x+c)-b \cos (b x+c)]}{\sin ^{2}(b x+c)}
Option C is correct because the derivative is found using the quotient rule and simplifying the resulting expression.

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