JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

1 Easy

1 of 1

Analyzing +4 | -1

Let

x = \frac{{a + 2b}}{{a + b}}

and

y = \frac{a}{b},

wherer

a

and

b

are positive integers. If

{y^2} > 2,

then

View answer and explanation

Correct option: B

{x^2} < 2

Option B (

{x^2} < 2

) is correct because substituting y = a/b into the equation for x and using the given condition

{y^2} > 2

leads to

{x^2} < 2

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