If $u = {x^2} + {y^2}$ and $x = s + 3t,y = 2s - t,$ then $\frac{{{d^2}u}}{{d{s^2}}}$ is equal to

JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

1 of 1

Application +4 | -1

u = {x^2} + {y^2}

and

x = s + 3t,y = 2s - t,

then

\frac{{{d^2}u}}{{d{s^2}}}

is equal to

View answer and explanation

Correct option: D

Option D (10) is correct because it is the result of applying the chain rule and differentiating twice with respect to s.

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