Question

If $ y=\log x \cdot e^{\left(	an x+x^{2}ight)} $, then $ \frac{d y}{d x} $ is equal to

Accepted Answer

$ e^{\left(	an x+x^{2}ight)}\left[\frac{1}{x}+\left(\sec ^{2} x+2 xight) \log xight] $

Answer

$ e^{\left(	an x+x^{2}ight)}\left[\frac{1}{x}+\left(\sec ^{2} x+xight) \log xight] $

Answer

$ e^{\left(	an x+x^{2}ight)}\left[\frac{1}{x}+\left(\sec ^{2} x-xight) \log xight] $

Answer

$ e^{\left(	an x+x^{2}ight)}\left[\frac{1}{x}+\left(\sec ^{2} x-2 xight) \log xight] $

JEE MATHEMATICS MCQ: DIFFERENTIATION

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