The value of ${\cot ^{ - 1}}9 + {\rm{cose}}{{\rm{c}}^{ - 1}}\frac{{\sqrt {41} }}{4}$ is

JEE MATHEMATICS MCQ: INVERSE TRIGONOMETRY

1 Easy

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Application +4 | -1

The value of

{\cot ^{ - 1}}9 + \mathrm{cose}{\mathrm{c}^{ - 1}}\frac{{\sqrt {41} }}{4}

View answer and explanation

Correct option: B

\frac{\pi }{4}

Option B (

\frac{\pi}{4}

) is correct because by converting to arctangent and using the arctangent addition formula, the expression simplifies to

\tan^{-1}(1)

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