JEE MATHEMATICS MCQ: DIFFERENTIATION

1 Easy

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Analyzing +4 | -1

Let

f\left( x \right) = {\left( {{x^3} + 2} \right)^{30}}

. If

{f^n}\left( x \right)

is a polynomial of degree 20, where

{f^n}\left( x \right)

denotes the

{n^{th}}

order derivative of

f\left( x \right)

with respect to

x

, then the value of

n

View answer and explanation

Correct option: C

Option C (70) is correct because the degree of the nth derivative is 90-n, and we want this to be 20, so n=70.

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